8y^2=-14y+4

Solution for 8y^2=-14y+4 equation:

8y^2=-14y+4

We move all terms to the left:

8y^2-(-14y+4)=0

We get rid of parentheses

8y^2+14y-4=0

a = 8; b = 14; c = -4;
Δ = b2-4ac
Δ = 142-4·8·(-4)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14)-18}{2*8}=\frac{-32}{16}
=-2
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14)+18}{2*8}=\frac{4}{16}
=1/4
$